This post demonstrates difference between
Look at the java bytecode of the program.
In code column, line #8 shows the bytecode representation of calling
Consider the bytecode, in code column line #18 shows the bytecode representation of calling
The documentation tells that the null reference is handled if null reference is passed. If argument is
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print(null.tostring())
and print(null)
in Java programming.
The difference isConsider the below sample code to understand the concept clearly.print(null.tostring())
throws null pointer exception butprint(null)
doesn't. Why?
public class NPETest { public static void main(String[] args) { Object obj1 = null; Object obj2 = null; System.out.print(obj1.toString()); //throws Null Pointer Exception System.out.print(obj2); // prints null } }
The statement System.out.print(obj1.toString())
causes following runtime exception.
Exception in thread "main" java.lang.NullPointerException at com.org.s20150310072124635.NPETest.main(NPETest.java:5)
The statement System.out.println(obj2)
runs fine and prints a text "null".
Why an exception is caused?
Look at the java bytecode of the program.
> javap -classpath target\test-classes -c NPETest Compiled from "NPETest.java" public class NPETest extends java.lang.Object{ public NPETest(); Code: 0: aload_0 1: invokespecial #8; //Method java/lang/Object."<init>":()V 4: return public static void main(java.lang.String[]); Code: 0: aconst_null 1: astore_1 2: aconst_null 3: astore_2 4: getstatic #17; //Field java/lang/System.out:Ljava/io/PrintStream; 7: aload_1 8: invokevirtual #23; //Method java/lang/Object.toString:()Ljava/lang/String; 11: invokevirtual #27; //Method java/io/PrintStream.print:(Ljava/lang/String;)V 14: getstatic #17; //Field java/lang/System.out:Ljava/io/PrintStream; 17: aload_2 18: invokevirtual #33; //Method java/io/PrintStream.print:(Ljava/lang/Object;)V 21: return }
In code column, line #8 shows the bytecode representation of calling
obj1.toString()
. Here obj1
is null
and so any attempt on a method invocation on null
results in a NullPointerException
.
Why print(null) works fine?
Consider the bytecode, in code column line #18 shows the bytecode representation of calling
print(obj2)
. Here object is passed as a parameter to the PrintStream.print()
method. According to the Java documentation, the source code will tell you that why this does not result in NullPointerException
.public void print(Object obj) { write(String.valueOf(obj)); } public static String valueOf(Object obj) { return (obj == null) ? "null" : obj.toString(); }
The documentation tells that the null reference is handled if null reference is passed. If argument is
null
, then a string equal to "null"; otherwise, the value of obj.toString()
is returned. So this statement does not result in NullPointerException
.
Summary -
print(null.tostring())
causes Null Pointer Exception.
print(null)
prints text "null".
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